Respuesta :

naǫ
[tex]5a-(8-a)=4a-10 \\ 5a-8+a=4a-10 \\ 6a-8=4a-10 \\ 6a-4a=-10+8 \\ 2a=-2 \\ a=-1[/tex]
luana
[tex]5a-(8-a)=4a-10\ \ \ |Omit\ the\ bracket\\\\ 5a-8+a=4a-10\\\\ 6a-8=4a-10\ \ \ |Subtract\ 4a\\\\ 2a-8=-10\ \ \ |Add\ 8\\\\ 2a=-2\ \ |Divide\ by\ 2\\\\ \boxed{a=-1}[/tex]