dlynnsian
dlynnsian dlynnsian
  • 26-04-2019
  • Mathematics
contestada

If y varies directly as x and y = 8 when x = 4, what is the value of y when x = 16?

Respuesta :

dalilavelez2019 dalilavelez2019
  • 26-04-2019

Answer:

32

Step-by-step explanation:

because when x=4 it became x=16 by multiplying by 4 so if you multiply 8 from y=8 by 4 it becomes 32

Answer Link
altavistard
altavistard altavistard
  • 26-04-2019

Answer:

y is 32 when x has the value 16

Step-by-step explanation:

The equation governing this relationship has the form y = kx.

Replacing y with 8 and x with 4, we get 8 = 4k, so that k = 2 is the constant of proportionality.

Then y = 2x.  When x = 16, y = 2(16) = 32.

y is 32 when x has the value 16.

Answer Link

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