kyleemoryowwcrq kyleemoryowwcrq
  • 25-03-2019
  • Mathematics
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9...................

9 class=

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carlosego
carlosego carlosego
  • 25-03-2019

For this case we must evaluate the following expression:

[tex]\sqrt [4] {16}[/tex]

We have by definition of properties of powers and roots that:

[tex]\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}[/tex]

On the other hand, we can rewrite the 16 as:

[tex]16 = 2 * 2 * 2 * 2 = 2 ^ 4[/tex]

So:

[tex]\sqrt [4] {16} = \sqrt [4] {2 ^ 4} = 2 ^ {\frac {4} {4}} = 2 ^ 1 = 2[/tex]

ANswer:

Option D

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