Answer:
21
Step-by-step explanation:
Note that n! = n(n - 1)(n - 2) ..... × 3 × 2 × 1, thus
7! = 7 × 6 × 5 × 4 × 3 × 2 × 1
5! = 5 × 4 × 3 × 2 × 1
2! = 2 × 1
Hence
cancel 5 × 4 × 3 × 2 × 1 on numerator/ denominator, leaving
[tex]\frac{7(6)}{2(1)}[/tex] = [tex]\frac{42}{2}[/tex] = 21
