sarabara18
sarabara18 sarabara18
  • 26-02-2019
  • Mathematics
contestada

What are the domain restrictions of the function f(x) = the quantity of x squared plus 6x plus 9, all over 3x plus 15.

Respuesta :

jimrgrant1 jimrgrant1
  • 26-02-2019

Answer:

x = - 5

Step-by-step explanation:

Given

f(x) = [tex]\frac{x^2+6x+9}{3x+15}[/tex]

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.

solve : 3x + 15 = 0 ⇒ 3x = - 15 ⇒ x = - 5 ← excluded value

Domain x ∈ R , x ≠ - 5

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