Answer:
a) (f + g)(x) ≥ 3 for all values of x.
Step-by-step explanation:
Given:
f(x) = l x l + 9 and g(x) = -6
(f + g)(x) = f(x) + g(x)
Now plug in the given functions
= l x l + 9 + (-6) +(-6) = -6
Therefore, (f + g)(x) = l x l + 9 - 6
(f + g)(x) = lxl + 3
Here the absolute value is always greater than or equal to zero.
So for values of x, lxl ≥ 0
There is already +3,
Therefore, (f + g)(x) ≥ 3 for all values of x.
Hope you will understand the concept.
Thank you.
