Alvarez25 Alvarez25
  • 24-02-2019
  • Mathematics
contestada

axis of symmetry of h=-16t^2+20t+6​

Respuesta :

jimrgrant1 jimrgrant1
  • 24-02-2019

Answer:

t = [tex]\frac{5}{8}[/tex]

Step-by-step explanation:

Given a parabola in standard form : ax² + bx + c : a ≠ 0

Then the axis of symmetry is

x = - [tex]\frac{b}{2a}[/tex]

h = - 16t² + 20t + 6 is in standard form

with a = - 16 and b = 20, hence

t = - [tex]\frac{20}{-32}[/tex] = [tex]\frac{5}{8}[/tex] ← axis of symmetry

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