Consider the upward direction of motion as positive and downward direction of motion as negative.
a = acceleration due to gravity in downward direction = - 9.81 [tex]\frac{m}{s^{2}}[/tex]
v₀ = initial velocity of runner in upward direction = 2.0 [tex]\frac{m}{s}[/tex]
v = final velocity of runner at the highest point = 0 [tex]\frac{m}{s}[/tex]
x = distance by which center of mass of runner rise = ?
Using the kinematics
v² = v²₀ + 2 a x
inserting the values
0² = 2² + 2 (- 9.81) x
x = 0.204 m
