jwbri
jwbri jwbri
  • 22-01-2019
  • Mathematics
contestada

solve with explanation please

solve with explanation please class=

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gmany
gmany gmany
  • 22-01-2019

Answer: [tex]\boxed{\dfrac{2}{5}}[/tex]

f(3)

Put the value of x = 3 to the equation of the function

[tex]f(x)=\dfrac{4}{5}x-2\\\\f(3)=\dfrac{4}{5}\cdot3-2=\dfrac{4\cdot3}{5}-2=\dfrac{12}{5}-\dfrac{10}{5}=\dfrac{12-10}{5}=\boxed{\dfrac{2}{5}}[/tex]

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