tiffanyliu1 tiffanyliu1
  • 22-12-2018
  • Mathematics
contestada

Given: ∆AFD, m ∠F = 90°
AD = 14, m ∠D = 30°
Find: Area of ∆AFD

I need an answer asap thanks

Respuesta :

gmany
gmany gmany
  • 22-12-2018

We have the triangle 30° - 60° - 90°.

The sides are in proportion: 2 : √3 : 1

(look at the picture).

[tex]2a=14[/tex]       divide both sides by 2

[tex]a=7[/tex]

[tex]a\sqrt3=7\sqrt3[/tex]

The area of a trinagle AFD:

[tex]A_{\Delta}=\dfrac{1}{2}(7)(7\sqrt3)=\boxed{\dfrac{49\sqrt3}{2}}[/tex]

Ver imagen gmany
Answer Link
barbarda barbarda
  • 08-12-2020

Answer:

A=7

Step-by-step explanation:

Hope this Helps!

Answer Link

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