fahadfaria2015 fahadfaria2015
  • 23-11-2018
  • Mathematics
contestada

Find the value of k, for which one root of quadratic equation kx²-14x+8=0 is 2

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jimrgrant1 jimrgrant1
  • 23-11-2018

k = 5

since x = 2 is a root then f(2) = 0

substitute x = 2 into the equation

4k - 28 + 8 = 0

4k - 20 = 0 ( add 20 to both sides )

4k = 20 ( divide both sides by 4 )

k = 5


Answer Link
Аноним Аноним
  • 23-11-2018

If one  root is 2 then

k(2)^2 - 14(2) + 8 = 0

4k - 28 + 8 = 0

4k = 28 - 8

4k = 20

k = 5   (answer)

Answer Link

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