Respuesta :

mathstudent55

[tex] \dfrac{\sqrt[3]{3}}{\sqrt[3]{2x}} = [/tex]

[tex] = \dfrac{\sqrt[3]{3}}{\sqrt[3]{2x}} \times \dfrac{\sqrt[3]{4x^2}}{\sqrt[3]{(2x)^2}} [/tex]

[tex] = \dfrac{\sqrt[3]{12x^2}}{\sqrt[3]{(2x)^3}} [/tex]

[tex] = \dfrac{\sqrt[3]{12x^2}}{2x} [/tex]

23greetri

Answer:

A. [tex]\frac{\sqrt[3]{12x^{2} } }{2x}[/tex]

Step-by-step explanation:

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