sara5494 sara5494
  • 21-11-2018
  • Mathematics
contestada

Can someone help with this

Can someone help with this class=

Respuesta :

alessandroarenas
alessandroarenas alessandroarenas
  • 21-11-2018

[tex]T(l) = T = 2\pi \sqrt{\frac{l}{32.2} \\[/tex]

[tex]T^2 = 4\pi^2 \frac{l}{32.2}\\32.2T^2 = 4\pi^2 l\\\frac{32.2}{4\pi^2}T^2 = l\\l (T)= \frac{8.05}{\pi^4} T^2[/tex]


Then if T = 3s

[tex]l(3) = \frac{8.05}{4\pi^2}(3^2)ft[/tex]

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