If a function is even, then f(-x) = x.
If a function is odd, then f(-x) = -x.
y = x³ + x² → f(x) = x³ + x² → -f(x) = -(x³ + x²) = -x³ - x²
f(-x) = (-x)³ + (-x)² = [(-1)(x)]³ + [(-1)(x)]² = (-1)³x³ + (-1)²x²
= -1x³ + 1x² =-x³ + x²
f(-x) ≠ f(x) and f(-x) ≠ -f(x)
y = x³ + x² is not odd and not even
Answer: neither
