24-10-2018
Mathematics

contestada

What is the solution

What is the solution class=

Respuesta :

25-10-2018

[tex](6x^5-21x^3+15x):3x=\dfrac{6x^5}{3x}-\dfrac{21x^3}{3x}+\dfrac{15x}{3x}=2x^4-7x^2+5\\\\Answer:\ (6x^5-21x^3+15x):3x=2x^4-7x^2+5\\\\Used\\\\\dfrac{a^n}{a^m}=a^{n-m}[/tex]

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