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  • 24-08-2018
  • Chemistry
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What is the molality of a solution made by dissolving 6 moles of naoh in 3 kg of water?

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Myotis Myotis
  • 02-09-2018

Answer: Molality = 2 mol/Kg or 2m  

Molality is a property of a solution and is defined as the number of moles of solute per kilogram of solvent. The SI unit for molality is mol/kg or 'm'.

[tex]Molality(m)=\frac{(Moles of solute)}{(Mass of solvent in Kg)}[/tex]

In our question , Solute is NaOH and solvent is water.

Moles of solute NaOH = 6 mol

Mass of solvent water = 3 kg

[tex]Molality(m)=\frac{(6 mol)}{(3 Kg)}[/tex]

[tex]Molality(m)=\frac{2mol}{kg}[/tex]  

Molality = 2m

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