In this question , it is given that slope of 5 and a y-intercept of (0,-2) .
Now we have to check out the equation of the line that we are gonna use here.
Here we use the slope intercept form, which is
[tex] y = mx + b [/tex]
where m is the slope , which is 5 here and y intercept is b , which is -2 here.
Substituting these values in the equation, we will get
[tex] y=5x-2 [/tex]
Part b .
Now we have to substitute 0 for y, and find the value of x, that is
[tex] 0 = 5x-2
\\
5x=2
\\
x = \frac{2}{5} [/tex]
