TRUEBOSS72
TRUEBOSS72 TRUEBOSS72
  • 23-08-2018
  • Mathematics
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mathmate
mathmate mathmate
  • 23-08-2018

Perimeter of ABDE = 2+6+2+6 = 16

Perimeter of BCD:

Length BC = sqrt(3^2+4^2)=sqrt(9+16)=sqrt(25) = 5 [using Pythagoras]

Length CD = Length BC = 5

Length BD = 6

Perimeter of BCD = 5+5+6 = 16

=>

ratio of perimeters = 16:16 = 1:1


Area of figure

= area of rectangle + area of triangle

= 2*6 + 6*4/2

= 12+12

=24

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