jakebahan
jakebahan jakebahan
  • 21-08-2018
  • Mathematics
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Please help me solve

Please help me solve class=

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gmany
gmany gmany
  • 27-08-2018

[tex] m\angle ADC=m\angle ADB+m\angle BDC\\\\m\angle ADC=112^o,\ m\angle ADB=6x+7,\ m\angle BDC=12x-3\\\\\text{substitute}\\\\(6x+7)+(12x-3)=112\\\\(6x+12x)+(7-3)=112\\\\18x+4=112\ \ \ \ |-4\\\\18x=108\ \ \ \ |:18\\\\x=6\\\\m\angle ADB=6x+7\to m\angle ADB=(6(6)+7)^o=(36+7)^o=43^o [/tex]

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