actofvalor228
actofvalor228 actofvalor228
  • 23-07-2018
  • Mathematics
contestada

Please help with this question

Please help with this question class=

Respuesta :

DeanR
DeanR DeanR
  • 23-07-2018

[tex] T = 2\pi \sqrt{\dfrac{L}{32}} [/tex]


[tex] \dfrac{T}{2\pi} = \sqrt{\dfrac{L}{32}} [/tex]


[tex]L = \dfrac{32 T^2}{4\pi^2} = \dfrac{8T^2}{\pi^2} [/tex]


[tex]L = \dfrac{32 (2.2)^2}{4(3.14)^2} =3.927 \textrm{ feet}[/tex]


Second choice: 4 feet




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