taylorlawrence27651 taylorlawrence27651
  • 21-07-2018
  • Chemistry
contestada

The ionization constant for water (kw) is 9.311 × 10−14 at 60 °c. calculate [h3o+], [oh−], ph, and poh for pure water at 60 °c.

Respuesta :

Phoca Phoca
  • 30-07-2018

As,

Kw = [H+] [OH-]

For water, [H+] = [OH-]

Therefore we can write

Kw = [H+]²

9.311 × 10-14 = [H+]²

[H+] = 3.04 × 10-7 = [OH-]

Ph = - log [H+]

= - log ( 3.04 × 10-7)

= 6.52

Thus, Ph = PoH = 6.52

Answer Link

Otras preguntas

Photograph is 3.5in.wide and 5in.long a newspaper editor has the photo enlarged to fit a space 7in.long how wide is the enlarged photograph?
What is the are ways to stay healthy?
If your laptop is not able to connect to your wireless network, which of the following might be a likely cause of the problem? A. The display screen on the l
what is the monthly payment for a loan if the amount to finance is 12385, the apr is 6.9% for 5 years and the monthly payment per $100 is $2.24
A resolute man is: a. determined. c. cautious. b. shy
What king died in the French Revolution??
Eighly percent of the tickets for the baseball game on july 4th have been sold. there are 20,00 tickets. how many havr been sold?
The __________ and __________ systems work together to support the body and enable it to move. a. skeletal and muscular b. muscular and endocrine c. lymphatic
Turn the sentences into the passive.; Can someone help me because I find it a little difficult?
How will technology and technological careers impact the 21st century?