as3lacruz24 as3lacruz24
  • 25-05-2018
  • Mathematics
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Take 2y^3-3y-5 from y^3-6y^2+5y

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choixongdong
choixongdong choixongdong
  • 25-05-2018
Take 2y^3-3y-5 from y^3-6y^2+5y
so

y^3- 6y^2+ 5y - (2y^3-3y-5)
=  y^3 - 6y^2 + 5y - 2y^3 + 3y + 5
= -y^3 - 6y^2 + 8y + 5

hope it helps
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