jazclaark12
jazclaark12
24-05-2018
Mathematics
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need answer to this asap!
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gmany
gmany
30-05-2018
[tex]\dfrac{2\pi}{3}\ is\ in\ II\ quadrant[/tex]
[tex]The\ reference\ angle\ is\ \pi-\dfrac{2\pi}{3}=\dfrac{3\pi}{3}-\dfrac{2\pi}{3}=\dfrac{\pi}{3}[/tex]
[tex]\boxed{Answer:\ B.\ \dfrac{\pi}{3}}[/tex]
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