the correct name of the hydrate iron (ii) sulfite is iron(ii)sulfite heptahydrate
it is gotten as below
find the % composition of FeSO4 = 100-44.26 =55.74 %
find the mole of FeSO4 and H20
= % composition/molar mass
FeSo4 =55.74/151.9 = 0.367 moles
H2O = 44.26/18 =2.459 moles
find the mole ratio by diving each mole with smallest mole
FeSO4 = 0.367/0.367 = 1
H2O = 2.459/0.367 = 7
therefore the name is iron (ii) sulfite heptahydrate is it has seven water molecules
