gusperez21 gusperez21

25-02-2016
Chemistry

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how many L of a .05 M HCL solution can be made by diluting 250 ml of 10 M HCL

Respuesta :

Willchemistry Willchemistry

25-02-2016

Mi * Vi = Mf * Vf

10 * 0.25 = 0.05 * Vf

2.5 = 0.05* Vf

Vf = 2.5 / 0.05

Vf = 50 L

hope this helps!

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