Add 4 to both sides so that the equation becomes -2x^2 + 6x + 5 = 0. To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0 x = [ -b ± √(b^2 - 4ac) ] / (2a) x = [ -6 ± √((6)^2 - 4(-2)(5)) ] / ( 2(-2) ) x = [-6 ± √(36 - (-40) ) ] / ( -4 ) x = [-6 ± √(76) ] / ( -4) x = [-6 ± 2*sqrt(19) ] / ( -4 ) x = 3/2 ± -sqrt(19)/2 The answers are 3/2 + sqrt(19)/2 and 3/2 - sqrt(19)/2.